Exersice 2.4 Class 10 NCERT Solutions pdf with small and detailed answers

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 NCERT Solutions for Class 10 Maths Chapter 2 Polynomials

 

Chapter 2- Polynomials Exercise Ex.2.4



here it is solution of question 1

Chapter 2 - Polynomials Exercise Ex. 2.4

Solution 1


Ncert Solutions Cbse Class 10 Mathematics Chapter - Polynomials

On comparing the given polynomial with the polynomial ax3 + bx2 + cx + d, we obtain a = 2, b = 1, c = -5, d = 2

Ncert Solutions Cbse Class 10 Mathematics Chapter - Polynomials

Thus, the relationship between the zeroes and the coefficients is verified.

Ncert Solutions Cbse Class 10 Mathematics Chapter - Polynomials

On comparing the given polynomial with the polynomial ax3 + bx2 + cx + d, we obtain a = 1, b = -4, c = 5, d = -2.

Ncert Solutions Cbse Class 10 Mathematics Chapter - Polynomials

Thus, the relationship between the zeroes and the coefficients is verified.

Concept insight: The zero of a polynomial is that value of the variable which makes the polynomial 0. Remember that there are three  relationships between the zeroes of a cubic polynomial and its coefficients which involve the sum of zeroes, product of all zeroes and the product of zeroes taken two at a time.
 

 

 

 

Chapter 2- Polynomials Exercise Ex.2.4



here it is solution of question 2

Solution 2
Let the polynomial be ax3  + bx2 + cx + d and its zeroes be Ncert Solutions Cbse Class 10 Mathematics Chapter - Polynomials  .
According to the given information:

Ncert Solutions Cbse Class 10 Mathematics Chapter - Polynomials

If a = k, then b = -2k, c = -7k, d = 14k

Thus, the required cubic polynomial is k(x3 - 2x2 - 7x + 14), where k is any real number.
The simplest polynomial will be obtained by taking k = 1.

Concept insight: A cubic polynomial involves four unknowns and we have three relations involving these unknowns, so the coefficients of the cubic polynomial can be found by assuming the value of one unknown and then finding the other three unknowns from the three relations.

 

 Chapter 2- Polynomials Exercise Ex.2.4



here it is solution of question 3

 
Solution 3
Let p(x) = x3 - 3x2 + x + 1
The zeroes of the polynomial p(x) are given as a - b, a, a + b.
Comparing the given polynomial with dx3 + ex2 + fx + g, we can observe that
d = 1, e = -3, f = 1, g = 1


Ncert Solutions Cbse Class 10 Mathematics Chapter - Polynomials

Therefore, the zeroes of p(x) are 1-b, 1, 1+b .

Ncert Solutions Cbse Class 10 Mathematics Chapter - Polynomials

Concept insight: When the polynomial and its zeroes are given then, remember to apply relationships between the zeroes and coefficients .
These relations  involve the sum of the zeroes, product of zeroes and the product of zeroes taken two at a time.

Chapter 2- Polynomials Exercise Ex.2.4



here it is solution of question 4

 
Solution 4
Ncert Solutions Cbse Class 10 Mathematics Chapter - Polynomials

Therefore, x2 - 4x + 1 is a factor of the given polynomial.
For finding the remaining zeroes of the given polynomial, we will carry out the division of

Ncert Solutions Cbse Class 10 Mathematics Chapter - Polynomials

Hence, 7 and -5 are also zeroes of the given polynomial.

Concept insight: If a is a zero of a polynomial p(x), where degree of p(x) is greater than 1, then (x - a) will be a factor of p(x) that is when p(x) is divided by (x - a), then the remainder obtained will be 0 and the quotient will be a factor of p(x) using division algorithm.  Remember that if (x - a) and (x - b) are factors of a polynomial, then (x - a)(x - b) will also be a factor of that polynomial.

Chapter 2- Polynomials Exercise Ex.2.4



here it is solution of question 5

 
Solution 5
By division algorithm,
Dividend = Divisor x Quotient + Remainder
Divisor x Quotient = Dividend - Remainder



Ncert Solutions Cbse Class 10 Mathematics Chapter - Polynomials

It will be perfectly divisible by x2 - 2x + k.

Ncert Solutions Cbse Class 10 Mathematics Chapter - Polynomials


10 - a - 8 x 5 + 25 = 0
10 - a - 40 + 25 = 0
- 5 - a = 0
a = -5

Thus, k = 5 and a = -5.

Concept insight: When a polynomial is divided by any non-zero polynomial, then it satisfies the division algorithm which is as below:
Dividend = Divisor x Quotient + Remainder

Divisor x Quotient = Dividend - Remainder

So, from this relation, it can be said that the result (Dividend - Remainder) will be completely divisible by the divisor

 

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